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(0.016-x)(0.000327)=x^2
We move all terms to the left:
(0.016-x)(0.000327)-(x^2)=0
determiningTheFunctionDomain -x^2+(0.016-x)(0.000327)=0
We add all the numbers together, and all the variables
-x^2+(-1x+0.016)(0.000327)=0
We add all the numbers together, and all the variables
-1x^2+(-1x+0.016)(0.000327)=0
We multiply parentheses ..
-1x^2+(-0.000327x+5.232E-6)=0
We add all the numbers together, and all the variables
-1x^2+(-0.000327x+8.2220505264977)=0
We get rid of parentheses
-1x^2-0.000327x+8.2220505264977=0
a = -1; b = -0.000327; c = +8.2220505264977;
Δ = b2-4ac
Δ = -0.0003272-4·(-1)·8.2220505264977
Δ = 32.88820221292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.000327)-\sqrt{32.88820221292}}{2*-1}=\frac{0.000327-\sqrt{32.88820221292}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.000327)+\sqrt{32.88820221292}}{2*-1}=\frac{0.000327+\sqrt{32.88820221292}}{-2} $
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